dua benda bermuatan masingmasing 20c dan 40c.benda pada jarak 10 m berapa besar gaya coulumb

Materi Gaya Coulomb [tex] F = \frac{k \times q_1 \times q_2}{r^2} \\ = \frac{9 \times 10^9 \times 20 \times 40}{10^2} \\ = (9 \times 2 \times 4) \times 10^9 \times 10^2 \times 10^{-2} \\ = 72 \times 10^9 = \boxed{7,2 \times 10^{10}} [/tex]