Jika mean dari data:3x-2,15,x+3,3x,5,x+1,9,3,15,x+1,10 adalah 10,09 tentukan nila median dan kuartil atas!!! Beserta caranya??

Statistik

data : (3x-2),(15),(x+3),(3x), (5),(x+1),(9), (3) , (15),(x+1), (10)
jumlah data  = (3+1+3+1+1)x + (-2+15+3+5+1+9+3+15+1+10)=9x + 60
banyak data = 11
Mean = 10,09
 
Mean = jumlah data/ banyak data
10,09 = (9x+ 60)/ 11
9x + 60 = 11 (10,09)
9x + 60= 111
9x = 51
x = 51/9= 17/3
..
data
3x - 2 = 17-2 = 15
x+ 3 = 17/3 + 3 = 26/3
3x =17
x + 1= 17/3 + 1 = 20/3
..
15, 15, 26/3, 17, 5, 20/3, 9, 3, 15, 20/3, 10
urutkan --> 3, 5, 20/3, 20/3, 26/3, 9, 10, 15, 15, 15, 17
Me = data ke 1/2(11+1) = data ke  6 =  9
q3 = data ke 3/4 (11+1) =data ke 9  =15