Fisika

Pertanyaan

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1 Jawaban

  • F = 20 N
    x = 0.04 cm = 4 x 10^-4 m

    cari dulu konstanta pegasnya
    k = F / x = 20 / (4 x 10^-4)
    k = 5 x 10^4 N/m

    maka e.potensialnya
    E.p = ½ k x² = ½ 5 x 10^4 x (4x 10^-4)²
    e.p = 4 x 10^-3 joule