tolong di jawab ......!!!!!!

(x²+2x-2)/(x²-3x+4)>3 (jadikan ruas kanan 0)
(x²+2x-2)-3(x²-3x+4)/x²-3x+4 > 0
x²+2x-2-3x²+9x-12 /x²-3x+4> 0
-2x²+11x-14 / x²-3x+4 > 0
x²-3x+4 (definit (+))
-2x+11-14>0
-1×(2x²-11x+14)<0
-1×(2x-7)(x-2)<0
-2x+7<0
-2x<-7
x>7/2
x<2

HP={x<2 atau x>7/2}