Matematika

Pertanyaan

x-3y=9-2z
2x+4y-3z=-9
3x-2y+5z=12
nilai x+y-z adalah

1 Jawaban

  • x - 3y + 2z = 9 (i)
    2x + 4y - 3z = -9 (ii)
    3x - 2y + 5z = 12 (iii)

    Eliminasi i dgn ii
    x - 3y + 2z = 9 |x 2|
    2x + 4y - 3z = -9

    2x - 6y + 4z = 18
    2x + 4y -3z = -9
    ---------------------- (-)
    -10y + 7z = 27 (iv)

    Eliminasi ii dan iii
    2x + 4y - 3z = -9 |x 3|
    3x - 2y + 5z = 12 |x 2|

    6x + 12y - 9z = -27
    6x - 4y + 10z = 24
    ------------------------(-)
    16y - 19z = -51 (v)

    Eliminasi iv dan v
    -10y + 7z = 27 |x 19|
    16y - 19z = -51 |x 7|

    -190y + 133z = 513
    112y - 133z= -357
    ----------------------- (+)
    -78y = 156
    y= -2

    -10y + 7z = 27
    -10(-2) + 7z = 27
    7z= 27 - 20
    z = 7 : 7 = 1

    x - 3y + 2z = 9
    x = 9 - 2(1) + 3(-2)
    x = 9 - 8
    x= 1

    x + y - z = 1 - 2 - 1 = -2


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