kerucut memiliki jari jari 21 cm dan volume 9,240 cm3.berapa tinggi kerucut tsb

[tex]V=\frac{1}{3}\pi r^2t \\ 9240=\pi\times 21^2\times t \\ 9240 = \frac{22}{7}\times 21\times 21\times t \\ 9240=1386t \\ t=\frac{9240}{1386}=\frac{20}{3}[/tex]