diket = fungsi f=×⇒ 2x + 3 dengan dom { x/x ≤ 10 , x ∈ bil cacah. ditanya : a). tulislah semua anggota domain b). tentukan semua range fungsi f c). tentukan hi

a.  { 0 ,1,2,3,4,5,6,7,8,9,10} 
b. - F(0) = 2.0+3 = 0+3 = 3 
   - f(1) = 2.1+3=2+3=5
   - f(2) = 2.2+3=4+3=7
   -f(3) = 2.3+3=6+3=9
  - f(4) = 2.4+3= 8+3 = 11
  - f(5) = 2.5+3 = 13 
  - f(6) = 2.6+3 = 15
  - f(7)=2.7+3=17
  -f(8)=2.8+3 = 19'
  - f(9) = 2.9+3 = 21 
  -f(10)=2.10+3=23

- { 3,5,7,9,11,13,15,17,19,21,23}
C.{(0,3) , (1,5) ,( 2,7),(3,9),(4,11),(5,13),(6,15),(7,17),(8,19),(9,21),(10,23)}

SEMOGA MEMBANTU ^_^