kak tolong di jb inintugas besok

a. luas selimut
= phi x r x s
= 3,14 x 6 x 10
= 3,14 x 60
= 188,4 cm²
Luas kerucut
= phi x r² + phi x r x s
= 3,14 x 6 x 6 + 3,14 x 6 x 10
= 113,04 + 188,4
= 301,44 cm²

b. Luas selimut
= phi x r x s
= 3,14 x 10 x 26
= 816,4 cm²
Luas kerucut
= phi x r² + phi x r x s
= 3,14 x 10 x 10 + 3,14 x 10 x 26
= 314 + 816,4
= 1130,4 cm²

c. Luas selimut
408,2= phi x r x s
408,2= 3,14 x r x 26
408,2= 81,64 x r
408,2/81,64 = r
5 = r
r = 5 cm
Luas kerucut
= phi x r² + phi x r x s
= 3,14 x 5 x 5 + 3,14 x 5 x 26
= 78,5 + 408,2
= 486,7 cm²

maaf kalo salah