Tolong dijawab ya gan

ELASTISITAS
• rangkaian pegas

k₁ = k₂ = 400 N/m
k₃ = k₄ = 300 N/m
m = 5 kg
g = 9,8 m/s²
∆x = __?


a][ konstanta pegas susunan

pegas k₁ dan k₂ tersusun seri
1/k₁₂ = 400/2 = 200 N/m

pegas k₃ dsn k₄ tersusun paralel
k₃₄ = 2×300 = 600 N/m

pegas k₁₂ dan pegas k₃₄ tersusun seri
k₁₂₃₄ = (1/200 + 1/600)⁻¹
k₁₂₃₄ = 600/4 = 150 N/m ← jwb


b][ pertambahan panjang
F = k₁₂₃₄ ∆x
m g = k₁₂₃₄ ∆x
∆x = m g / k₁₂₃₄
∆x = 5 • 9,8 / 150
∆x = 49/150 m ← jwb