Diketahui luas selimut suatu tabung 880cm².Jika phi 22/7 dan tinggi tabung 20 cm volume tabung tersebut adalah

Dik. Luas selimut tabung = 880 cm² & Tinggi = 20cm & π = 22/7
Dit. Volume tabung ?

Jawab...

Luas selimut tabung (Lst) = 2πrt
@ Lst = 2πrt
@ 880 = 2 x 22/7 x r x 20
@ 880 x 7/22 = 40 x r
@ 280 = 40 x r
@ r = 280/40
@ r = 7cm

Volume tabung = πr²t
@ V = πr²t
@ V = 22/7 x (7)² x 20
@ V = 22/7 x 49 x 20
@ V = 3080 cm³

Semoga membantu... ^_^