Matematika

Pertanyaan

Log 2 + log 200 - log 6 + log 5 - log 3 + log 18 - log 2

1 Jawaban

  • Log 2 + log 200 - log 6 + log 5 - log 3 + log 18 - log 2
    = log2 + log 200 + log 5 + log 18 - (log 6 + log 3 + log 2)
    = log (2 x 200 x 5 x 18) - log(6 x 3 x 2)
    = log 36.000 - log 36
    = log (36.000 : 36)
    = log 1.000
    = log 10³
    = 3. log 10
    = 3 . 1
    = 3

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