integral 3 akar (1/2x - 5) dx

Misal :
u = 1/2x - 5
du/dx = 1/2
dx = du/(1/2)
Integral 3 akar (1/2x - 5) dx = 3 u ^(1/2)* du/(1/2) = 3/(1/2)*integral u^(1/2)du = 6*1/(1/2+1)u^(1/2+1)+c = 6*2/3u ^3/2 +c = 4 u ^ (3/2) + c = 4*(1/2x - 5)*akar(1/2x - 5) + c