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Bab Luas Bangun Datar Bayangan dan Luas Daerah Segi Banyak
Sekolah Dasar Kelas VI

1. Luas = d1 × d2 ÷ 2 = 14 × 14 ÷ 2 = 98 cm2 (belah ketupat)

2. L1 = P × l = 12 × 24 = 288
L2 = a × t ÷ 2 = 18 × 12 ÷ 2 = 108
288 + 108 = 396 cm2

3. L1 = 3,14 × r × r = 3,14 × 7 × 7 = 153,86 cm2
L2 = ( a + b ) × t ÷ 2 = ( 20 + 14 ) × 14 ÷ 2 = 34 × 14 ÷ 2 = 238 cm2
153.86 + 238 = 391,86

4. p × l = 10 × 8 = 80 cm2

5. L1 = s × s = 14 × 14 = 196
L2 = a × t ÷ 2 = 14 × 14 ÷ 2 = 98
L3 = a × t ÷ 2 = 14 × 14 ÷ 2 = 98
L4 = a × t ÷ 2 = 14 × 14 ÷ 2 = 98
L5 = a × t ÷ 2 = 14 × 14 ÷ 2 = 98

196 + 98 + 98 + 98 + 98 = 588 cm3

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