Log(x+6) - log(x-3)=1
Matematika
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Pertanyaan
Log(x+6) - log(x-3)=1
2 Jawaban
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1. Jawaban azam81hakimi
Simplifying log(x + -6) + -1log(x + 3) = 1 Reorder the terms: glo(-6 + x) + -1log(x + 3) = 1 (-6 * glo + x * glo) + -1log(x + 3) = 1 (-6glo + glox) + -1log(x + 3) = 1 Reorder the terms: -6glo + glox + -1glo(3 + x) = 1 -6glo + glox + (3 * -1glo + x * -1glo) = 1 -6glo + glox + (-3glo + -1glox) = 1 Reorder the terms: -6glo + -3glo + glox + -1glox = 1 Combine like terms: -6glo + -3glo = -9glo -9glo + glox + -1glox = 1 Combine like terms: glox + -1glox = 0 -9glo + 0 = 1 -9glo = 1 Solving -9glo = 1 Solving for variable 'g'. Move all terms containing g to the left, all other terms to the right. Divide each side by '-9lo'. g = -0.1111111111l-1o-1 Simplifying g = -0.1111111111l-1o-1 -
2. Jawaban alakbar30
aturan log
• log a - log b = log a/b
• log 10 = 1
log(x +6) - log (x - 3) = 1
log ( x + 6)/ ( x - 3) = log 10
(x+6)/(x-3) = 10
(x+6)/(x-3) - 10 = 0
(x+6)/(x-3) - 10(x-3)/(x-3) = 0
(x+6) - 10 (x-3)
___________ = 0
(x-3)
maka X adalah :
• (x+6) - 10 (x-3) = 0
x+6 - 10x+30 = 0
- 9x + 36 = 0
-9x = -36
x = -36/-9 = 4
•
x-3 = 0
x = 3