Matematika

Pertanyaan

a.) 2log2+2log3-2log6+2log8=
b.) 3log729+3log9=

1 Jawaban

  • Materi Logaritma
    Jawaban A. [tex] ^2 \log 2 + ^2 \log 3 - ^2 \log 6 + ^2 \log 8 \\ = ^2 \log (\frac{2 \times 3 \times 8}{6})\\ = ^2 \log 8 = ^2 \log 2^3 = 3 [/tex] Jawaban B. [tex] ^3 \log 729 + ^3 \log 9 \\ = ^3 \log 3^5 + ^3 \log 3^2 \\= 5 + 2 = 7 [/tex]

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