diketahui (g o f)(x) = 4x²+4 dan g(x) = x²-1. tentukan nilai f(x-2) ?

g(f(x)) = 4x² + 4
f²(x) - 1 = 4x² + 4
f²(x) = 4x² + 5
f(x) = ± √4x² + 5
f(x - 2) = ± √(4(x - 2)² + 5)
= ± √(4x² - 16x + 21)

[tex](g\circ f)(x)=4x^2+4 \\ g(x)=x^2-1 \\ (g\circ f)(x)=g(f(x)) \\ g(f(x)) = 4x^2+4 \\ (f(x))^2-1=4x^2+4 \\ (f(x))^2=4x^2+5 \\ f(x)=\pm\sqrt{4x^2+5} \\ f(x-2)=\pm\sqrt{4(x-2)^2+5} \\ f(x-2)=\pm\sqrt{4(x^2-4x+4)+5} \\ f(x-2)=\pm\sqrt{4x^2-16x+16+5} \\ f(x-2)=\pm\sqrt{4x^2-16x+21}[/tex]