TOLONG BANGET :( 1.fungsi g dirumuskan g(x)= ax+b jika g(1)=-5 dan g(4)=4 maka rumus fungsinya adalah 2.Ditentukan f(x)=5-2x dengan daerah asal {-2,-1,0,1,2}. d

1.) g (x)= ax+b
g (1) = 1a+b= -5
g (4) = 4a+b= 4
------------------------- --
= -3a= -9
= a = 3

1a+b = -5
1 (3)+b = -5
3+b = -5
b = -5-(-3)
b = -5+3= -2

bentuk fungsi =
g (x)= ax+b
g (×)= 3a+(-2) atau 3a-2

2.) f (x)= 5-2x
domain = {-2,-1,0,1,2}

kodomain=
•f (-2) = 5-2 (-2)= 5+4= 9
•f (-1) = 5-2 (-1 )= 5+2= 7
•f (0) = 5-2 (0) = 5-0 =5
•f (1) = 5-2 (1) = 5-2 =3
•f (2) = 5-2 (2) = 5-4 =1

kodomain = {9,7,5,3,1}